In triangle ABC, angle C is straight, BC = 3√21, cosB = 0.4, find AB.

1) ▲ ABC;

∡ С – straight line;

ВС = 3 * √21, cos B = 0.4.

Find AB.

2) cos b = BC / AB;

Let us express AB.

cos b * AB = BC;

AB = BC / cos b;

3) Find AB.

AB = BC / cos b = 3 * √21 / (0.4) = 3 * √21 / (4/10) = 3 * √21 / (2/5) = 3 * √21 * 5/2 = 1 .5 * 5 * √21 = 7.5 * √21;

Answer: AB = 7.5 * √21.



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