In triangle ABC, angle C is straight, BC = 6, COS B = 0.3. find AB.
| August 30, 2021 | education
1) BC = 6;
cos b = 0.3;
2) Since cos b = 0.3, then sin b = 0.6.
3) Let’s write down the aspect ratio in a right-angled triangle for the cosine of an acute angle.
cos b = BC / AB.
4) Find BA.
cos b = BC / AB.
BA * cos b = BC;
AB = BC / cos b = 6 / 0.3 = 6 * 10 / (0.3 * 10) = 60/3 = 20;
Answer: AB = 20.
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