# In triangle ABC, angle C is straight, BC = 6, COS B = 0.3. find AB.

August 30, 2021 | education

| 1) BC = 6;

cos b = 0.3;

2) Since cos b = 0.3, then sin b = 0.6.

3) Let’s write down the aspect ratio in a right-angled triangle for the cosine of an acute angle.

cos b = BC / AB.

4) Find BA.

cos b = BC / AB.

BA * cos b = BC;

AB = BC / cos b = 6 / 0.3 = 6 * 10 / (0.3 * 10) = 60/3 = 20;

Answer: AB = 20.

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