In triangle ABC, angle C is straight, BC = 9, tg A = 0.75. Find an AC?
| July 1, 2021 | education
1) BC = 9;
tg a = 0.75;
2) Tangent of an acute angle – the ratio of the opposite leg to the hypotenuse.
tg a = BC / AC;
Let us express AC.
tg a * AC = BC;
AC = BC / tg a;
3) Find the AC.
AC = 9 / 0.75 = 9 / (75/100) = 9 / (3/4) = 9/1 * 4/3 = 9/3 * 4 = 3 * 4 = 12;
Answer: AC = 12.
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