In triangle ABC, angle C is straight, CD is perpendicular to the plane of the triangle. Find the distance from point D
| December 1, 2020 | education
In triangle ABC, angle C is straight, CD is perpendicular to the plane of the triangle. Find the distance from point D to the hypotenuse AB if AC = 3 cm, CB = 4 cm, CD = 1 cm.
1) AB = √ (9 + 16) = 5
2) CH⊥AB
3) CH = (AC * BC: 2) * 2 / AB = 2.4, TC S = CH * AB / 2 = AC * BC / 2
4) DH = √ (CD ^ 2 + CH ^ 2) = 2.6
Answer: 2.6
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