In triangle ABC, angles C and D are equal to 90 degrees, AC = 6, AD = 2. The hypotenuse of AB is equal to?

Triangle ACD is rectangular, in which, according to the Pythagorean theorem, CD ^ 2 = AC ^ 2 – AD ^ 2 = 36 – 4 = 32.

The height CD is drawn from the top of the right angle to the hypotenuse, then CD ^ 2 = AD * BD.

ВD = СD ^ 2 / АD = 32/2 = 16.

Then AB = AD + BD = 2 + 16 = 18 cm.



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