In triangle ABC, BC = √6, angle A = 60, angle B = 75; Find: AB

The sum of the inner angles of the triangle is 180, then the angle ACB = (180 – BAC – ABC) = (180 – 60 – 75) = 45.

In triangle ABC we apply the theorem of sines.

BC / SinBAC = AB / SinACB.

AB = BC * SinACB / SinBAC = √6 * (√2 / 2) / (√3 / 2) = (2 * √12) / (2 * √3) = 2 * √3 / √3 = 2 cm.

Answer: The length of the AB side is 2 cm.



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