In triangle ABC. BD bisector of angle B, angle A = 90 degrees, AD = √ 5, BC = 2√ 5. Find the BDC area.
| May 19, 2021 | education
Since BD is the bisector of the angle ABC, it divides the AC side into segments proportional to the adjacent sides.
AB / AD = BC / CD.
AB * CD = AD * BC = √5 * 2 * √5 = 10.
The AB leg is the height of the BDC triangle drawn to the CD side, then Svds = CD * AB / 2 = 10/2 = 5 cm2.
Answer: The area of the BDC triangle is 5 cm2.
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