In triangle ABC BD is the bisector; angle A = 40 degrees, angle ABD = 20 degrees Find angle C.

Since BD is the bisector of the angle ABC, then the angle ABD = CBD = 20, then the angle ABC = 2 * ABD = 2 * 20 = 40.

The sum of the inner angles of the triangle ABC is 180, then the angle ACB = 180 – BAC – ABC = 180 – 40 – 40 = 100.

Answer: The angle ABC is 100.



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