In triangle ABC, bisector CP divides side AB into segments AP = 4 cm, PB = 5 cm. Find the perimeter of the triangle if AC = 10cm.

CP is a bisector, then it divides the AB side in relation to AC: BC. Let’s substitute our values: 4: 5 = 10: BC; 4BC = 50; BC = 12.5. The perimeter of the trunk is: 9 + 10 + 12.5 = 31.5.



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