In triangle ABC, bisectors AA1 and BB1 intersect at point O. Find the ratio of the areas of triangles AOC

In triangle ABC, bisectors AA1 and BB1 intersect at point O. Find the ratio of the areas of triangles AOC and BOC if AC = 8 cm, BC = 6 cm.

The bisectors of a triangle intersect at one point. Since BB1 and AA1 are bisectors, then CO is the bisector of the angle ACB, then the angle OCA = OCB.

In the triangles AOC and BOS, the side of the OS is common.

Saos = AC * OC * SinOCA / 2 = 4 * OC * SinOCA.

Swax = BC * OC * SinOBC = 3 * OC * SinOBC.

Then Saos / Swos = 4 * OC * SinOCA / 3 * OC * SinOBC = 4/3.

Answer: The ratio of the areas of the triangles is 4/3.



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