In triangle ABC, bisectors AN and BL are drawn which intersect at point O. Angle AOB is 131. Find the outer angle at vertex C.

Since the angle AOB is equal to 131 degrees.
Knowing that the sum of the angles of a triangle is 180g.
This means that there will be two remaining.
180-131 = 49gr.
Further:
Considering that АN and BL are bisectors, the sum of the angles CAB and CBA is equal to:
49×2 = 98 gr.
Accordingly, the angle of the ВСA remains:
180-98 = 82 gr.
Hence:
The outer angle at the vertex C is equal to:
180-82 = 98gr.
Since the outer and inner corners are adjacent.
Answer: The outer corner is 98 degrees.