In triangle ABC C = 90, cos A = 3/10, find sinB
| March 3, 2021 | education
Given:
ABC – right triangle;
Angle C = 90 degrees;
cos A = 3/10;
Find sin B.
Decision:
1) cos A = AC / AB = 3/10;
Hence, AC = 3 and AB = 10.
2) Find the BC by the Pythagorean theorem.
BC = √ (AB ^ 2 – AC ^ 2) = √ (10 ^ 2 – 3 ^ 2) = √ (100 – 9) = √81 = 9;
3) sin B = AC / AB = 3/10;
Answer: sin B = 3/10.
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