In triangle ABC, C = 90 degrees, BC = 5. The area of the triangle is 20 cm. Find tg B.

Having in the condition the area of the triangle and the length of one of the legs, we determine the length of the other leg.

Sас = АС * ВС / 2.

AC = 2 * Savs / BC = 2 * 20/5 = 8 cm.

In a right-angled triangle, the tangent of the angle is equal to the ratio of the opposite leg to the adjacent leg.

tgABC = AC / BC = 8/5 = 1.6.

Answer: tgABC is 1.6.



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