In triangle ABC CH – height, AD – bisector, О – intersection point of lines CH, angle BAD = 12 degrees. Find the angle AOC.

Since AD is the bisector of the angle BAC, the angle BAD is equal to the angle BAC, then the angle BAC = 2 * BAD = 2 * 12 = 24.

The ACH triangle is rectangular, since the CH is the height in the AB side, then the angle ACH = 180 – AHC – CAH = 180 – 90 – 24 = 66.

In the AOC triangle, the angle AOC = 180 – CAO – ACH = 180 – 66 – 12 = 102.

Answer: The AOC angle is 102.



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