In triangle ABC, find the degree measure of angle B, if AB = √3 cm, AC = √2 cm, angle C = 60 degrees.

univerkov | August 29, 2021 | education

For the solution we use the theorem of sines for triangles.

Then AC / SinABC = AB / SinACB.

SinABC = AC * SinACB / AB = √2 * Sin60 / √3 = √2 * (√3 / 2) / √3 = √2 / 2.

Angle ABC = arcsin√2 / 3 = 45.

Answer: Angle ABC is 45.

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