In triangle ABC, it is known that AB = 5, AC = 7, and BC = √39. Find the radius of the circle circumscribed

In triangle ABC, it is known that AB = 5, AC = 7, and BC = √39. Find the radius of the circle circumscribed about this triangle.

Since here we are talking about a non-regular triangle (all sides are different), then the radius of the circle described around the triangle can be calculated by the formula
R = abc / 4S = abc / 4 √ (p (p-a) (p-b) (p-c))
p = (a + b + c) / 2
Find p = (5 + 7 + √39) / 2 approximately = 9.123, then the radius will be:
R = (5 * 7 * √39) / (4√ (9.123 (9.123-5) (9.123-7) (9.123-√39)) = 3.604cm
Answer: circle radius = 3.604cm