In triangle ABC, it is known that AB = BC, AM and CK are the medians of this triangle. Prove that MK || AC.

Since, by condition, CM and AM of the median of the triangle ABC, point K is the midpoint of the lateral side AB, and point M is the midpoint of the lateral side BC.

Then the segment KM is the midline of the triangle ABC, and therefore the MC is parallel to the AC, which was required to be proved.



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