In triangle ABC it is known that AB is equal to BC. The ABC angle is 144 degrees. Find corner B.

Since, by condition, AB = BC, the triangle ABC is isosceles with the base AC.
Then the angles at the base of the AC are equal. Angle BAC = BCA.
The sum of the inner angles of the triangle is 1800, then the angle BCA = (180 – ABC) / 2 = (180 – 144) / 2 = 18.
Answer: The BCA angle is 18.



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