In triangle ABC it is known that angle BAC = 45, angle ACB = 30, BC = 14√2. Find the length AB.

For the solution we use the theorem of sines for triangles.

AB / SinACB = CB / BAC.

14 * √2 / Sin30 = BC / Sin45.

14 * √2 / (1/2) = BC / (√2 / 2).

BC / 2 = (14 * √2) * (√2 / 2).

BC = 28 cm.



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