In triangle ABC, it is known that BAC = 48, AD is the bisector. Find the corner BAD.

We are given a triangle ABC. It is known that the BAC kut has 48 degrees. The bisector AD, which comes out of the Kuta BAS, divides the kut in half.

The task asks: how many degrees are in the kuta BAD?

We need kut BAC ÷ 2, that is:

48 ° ÷ 2 = 24 °

As a result, we got that kut BAD = 24 °



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