In triangle ABC, point M is the midpoint of side AB and angle A = angle B. Prove that AB is perpendicular to CM.
| May 4, 2021 | education
According to the condition, the angle CAB = CBA, hence the triangle ABC is isosceles AC = BC.
The segment AM, according to the condition, is equal to the segment BM, therefore AM is the median of the triangle ABC.
In an isosceles triangle, the median is also the bisector and the height, and the height drawn to the base is perpendicular to it, then CM _ | _ AB, which was required to prove.
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