In triangle ABC, side AB = 4√13 BC = 2√37 and AC = 2√7. Find the angle between the medians AM and CK.

1) Using the cosine theorem (c ^ 2 = a ^ 2 + b ^ 2 – 2 ab * cos (α), we find the angles of the triangle.

2) By definition, the median divides the side of a triangle in half. Using the property of the medians (the point of intersection of the medians divides them into segments in the ratio 2: 1) we find | AO | and | CO |.

3) From the triangle AOC, again using the cosine theorem, we find the angle AOC, which is the desired one.