In triangle ABC, side AB is 27 cm, and it is 3 times larger than side BC. Find the length of the side AC

In triangle ABC, side AB is 27 cm, and it is 3 times larger than side BC. Find the length of the side AC if the perimeter of triangle ABC is 61 cm.

By the condition of the problem:
| AB | = 27cm and | AB | = 3 | ВС |.
Respectively,
| Sun | = | AB | / 3 = 27/3 = 9cm.
The perimeter of a triangle is the sum of the lengths of its sides:
P = | AB | + | Sun | + | AC |
In our case:
P = 61cm
Substituting all known quantities into the equation for the perimeter, we get:
61 = 27 + 9 + | AC |
It follows that:
| AU | = 61 – 27 – 9 = 25cm
Answer: | AC | = 25cm