In triangle ABC, side AB is 27cm and one is 3 times more than side BC. Find the length of side AC

In triangle ABC, side AB is 27cm and one is 3 times more than side BC. Find the length of side AC if the perimeter of triangle ABC is 61cm.

Find the BC side:

The problem says that AB is 3 times more than BC.

BC = AB / 3, AB = 27cm;

BC = 27/3 = 9cm.

The perimeter of a triangle is equal to the sum of all sides.

P = AB + BC + AC = 61cm;

P = 27 + 9 + AC = 61cm.

From this equation, we can express the side of the AC:

AC = P – (AB + BC) = 61 – (27 + 9) = 25cm.

Answer: AC = 25cm.