In triangle ABC, side AB is 5 cm larger than side AC and 3 cm less than side BC

In triangle ABC, side AB is 5 cm larger than side AC and 3 cm smaller than side BC Find the sides of the triangle if the perimeter is 58 cm.

Given triangle ABC.

P = AB + AC + BC;

P = 58 cm;

Let x – side AB;

Since side AB is 5 cm larger than side AC, then side AC is x – 5 and 3 cm less than side BC, then side BC is x + 3.

Let’s make an equation and find the sides of the triangle.

x + x – 5 + x + 3 = 58;

x + x + x – 2 = 58;

3 * x = 58 + 2;

3 * x = 60;

x = 60/3;

x = 20;

Means:

Side AB is 20 cm;

The speaker side is 20 cm – 5 cm = 15 cm;

The BC side is 20 cm + 3 cm = 23 cm.

Answer: AB = 20 cm, AC = 15 cm and BC = 23 cm.