In triangle ABC, side BC = 16 cm, angle B = 150 °, area of the triangle 24 cm2. Find the AB side.

We use the formula for the area of a triangle in terms of the sine.

The area of triangle ABC is equal to half the product of sides AB and BC by the sine of angle B.

Let us denote the side of AB by x.

1/2 * x * 16 * sin150 ° = 24,

8x * sin (180 ° -30 °) = 24,

x * sin30 ° = 3,

x * 1/2 = 3,

x = 6.

Answer: AB = 6 cm.



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