In triangle ABC, side BC = 3√2 cm, side AB = 4 cm, and side AC = √10 cm. using the cosine theorem, find the angle b.

Cosine theorem
AC2 = AB2 + BC2 – 2 AB BC cos∠B
cos B = AB ^ 2 + BC ^ 2-AC ^ 2 – 2AB * BC * сosB = (substitute values) = √2 / 2 = 45 degrees
Answer: ∠B = 45 °



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