In triangle ABC, sides AB and BC are equal. The AC side is 15 cm. The perimeter of the triangle is 65 cm.

In triangle ABC, sides AB and BC are equal. The AC side is 15 cm. The perimeter of the triangle is 65 cm. What is the length of the AB side?

From the condition of the problem, the perimeter of the triangle and the length of one of its sides – the base – are known, and since it is isosceles, the sides are equal. Let’s answer the question of the problem and define the AB side.

(65 – 15) / 2 = 50/2 = 25 centimeters.

Answer: 25 centimeters.



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