In triangle ABC, sides AB and BC are equal. The outer angle at apex A of the base of the AC is 162 °.

In triangle ABC, sides AB and BC are equal. The outer angle at apex A of the base of the AC is 162 °. Find the angles at the base in triangle ABC.

Given:
triangle ABC; AB = BC
angle A = 162 degrees
Find: base angles
Decision:
Since the sides AB and BC are equal, the triangle ABC is isosceles, which means that the angles BAC and BCA are equal (angles at the base);
angle BAC = 180 ° -162 ° = 18 °
Answer: 18 °



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