In triangle ABC, sinA = 0.6, sinB = 0.8. Find sin C
| September 16, 2021 | education
Determine the cosine of the angle BAC.
Cos2BAC = 1 – Sin2BAC = 1 – (6/10) 2 = 1 – 36/100 = 64/100.
CosBAC = √ (64/100) = 8/10 = 4/5 = 0.8.
Then CosBAC = SinABC, and therefore, triangle ABC is right-angled by the theorem on the equality of sine and cosine of different angles in a right-angled triangle.
Angle АСВ = 900.
SinACB = 1.
Answer: The sine of angle C is 1.
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