In triangle ABC, the angle c is 90 ° sin A = 0.3. Find cos B.
| May 11, 2021 | education
The sine of an acute angle of a right-angled triangle is the ratio of the opposite leg to the hypotenuse SinA = BC / AB.
The cosine of an acute angle of a right-angled triangle is the ratio of the adjacent leg to the hypotenuse CosB = BC / AB.
Then the sine of one acute angle of a right-angled triangle is equal to the cosine of another acute angle.
CosB = SinA = 0.3.
Answer: CosB = 0.3.
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