In triangle ABC, the angle is c, AB = 10, BC = 6. Find the sin of angle ABC.

As we can see from the condition of our problem, the AB side is the hypotenuse of our triangle, while the BC side is the adjacent leg of the ABC angle.

Let us determine what the cosine of the angle ABC will equal, when from the condition of the task we know that the hypotenuse is 10, while the required leg is 6:

6: 10 = 0.6.

Determine what the sine of the angle will equal, for which we use the well-known trigonometric equation:

sin2 B = 1 – (0.6) ^ 2;

sin2 B = 0.64;

sin1 B = 0.8;

sin2 V = -0.8 (not suitable).

Answer: 0.8.