In triangle ABC, the height CH is drawn, which divides the angle C into two angles, whose values are 47

In triangle ABC, the height CH is drawn, which divides the angle C into two angles, whose values are 47 degrees and 71 degrees. Find the smallest of the two remaining angles of the triangle.

Since CH is a height, it is perpendicular to the AB side, so the angle H is 90.

Now, taking advantage of the fact that the sum of the angles of the triangle is 180, we have: B = 180 – ВCH – ВНС = 180 – 71 – 90 = 19.

Similarly, A = 180 – AНС – НСA = 180 – 47 – 90 = 43.

Answer: 19.