In triangle ABC, the height CH is drawn, which divides the angle into two angles 1) 47 2) 71

In triangle ABC, the height CH is drawn, which divides the angle into two angles 1) 47 2) 71 find the smallest of the two remaining angles of the triangle ABC.

The height of CH divided the ABC triangle into two right-angled triangles.
Consider a right-angled triangle CHB. Let the angle C in this triangle be 47 °. Find angle B:
∠ B = 90 ° – 47 ° = 43 °.
Consider a right-angled triangle CHA and find the angle A in it:
∠ А = 90 ° – 71 = 19 °.
We got that the smaller angle is 19 °.
Answer: the degree measure of the smaller angle in the ABC triangle is 19 °.