In triangle ABC, the heights drawn from vertices B and C form angles of 40 and 17 degrees with side BC

In triangle ABC, the heights drawn from vertices B and C form angles of 40 and 17 degrees with side BC, respectively. Find the degree measure of angle A.

1. The height ВН forms a right angle with the base of the AC, therefore the angle BCA = 90 ° -40 ° = 50 °.
2. The height CE forms a right angle with the base AB, therefore the angle ABC = 90 ° -17 ° = 73 °.
3. Then the angle BAC = 180 ° – (50 ° + 73 °) = 57 °.
ANSWER: 57 °



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