In triangle ABC, the heights of AK and BE intersect at point O, angle ACO = 46 degrees. Find the angle ABO.

Let’s build the CM height. The heights of the triangle intersect at one point.

Since BE is the height, the triangle COE is rectangular, then the angle COE = (90 – OCE) = 90 – 46 = 44.

Angle MOB = COE = 44 as vertical angles.

The BOM triangle is rectangular, since CM is the height, then the angle MBO = ABO = 90 – 44 = 46.

Answer: The ABO angle is 46.



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