In triangle ABC, the length of side AB is 5 cm, side BC is 8 cm longer than side AB, and the length

In triangle ABC, the length of side AB is 5 cm, side BC is 8 cm longer than side AB, and the length of side AC is less than the sum of the lengths of sides AB and BC by 6 cm Find the perimeter of the triangle

The perimeter of a triangle is equal to the sum of the lengths of its three sides.

P = AB + BC + AC

The length of the AB side is known to us 5 cm. The length of the BC side is 8 cm longer than AB, which means it is (5 + 8) cm. The length of the AC side is 6 cm less than the sum of the lengths of the AB and BC sides. The sum of AB + BC = 5 + (5 + 8), and then AC = (5 + (5 + 8)) – 6.

P = 5 + (5 + 8) + ((5 + (5 + 8)) – 6) = 5 + 13 + (5 + 13 – 6) = 18 + 12 = 30 (cm)

Answer. 5 + (5 + 8) + ((5 + (5 + 8)) – 6); 30 cm.