In triangle ACB, side AB = 12 cm and angle ACB = 30 degrees. Find the radius of the circumscribed circle?

To solve the problem, recall the theorem of sines: in an arbitrary triangle, the ratio of the side of the triangle to the sine of the opposite angle is equal to the diameter of the circle circumscribed about it.
a / sin a = 2 R
sin 30 ° = 1/2
12: (1/2) = 2 R
12 * 2: 2 = R
R = 12.
Answer: the radius of the circumscribed circle is 12 centimeters.



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