In triangle CAB, angle C = 90 degrees. CA = 4, AB = 5, BC = 3. Find sine B, cosine B, tangent B.
| May 19, 2021 | education
1) The sine of an acute angle of a right-angled triangle is the ratio of the leg opposite to this angle to the hypotenuse.
sin B = AC / AB; sin B = 4/5 = 0.8.
2) The cosine of an acute angle of a right-angled triangle is the ratio of the leg adjacent to this angle to the hypotenuse.
sin B = BC / AB; sin B = 3/5 = 0.6.
3) The tangent of an acute angle of a right-angled triangle is the ratio of the leg opposite to this angle to the adjacent leg.
tg B = AC / BC; tg B = 4/3.
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