In triangle CDE, angle C = 30, D = 45, CE = 5√2 find: DE
| September 8, 2021 | education
Let’s build the height ЕН.
The leg EH of the right-angled triangle CEН lies opposite the angle 30, then EH = EC / 2 = 5 * √2 / 2 cm.
The EDH triangle is rectangular and isosceles, then ED = √2 * 25 * 2/4 = √25 = 5 cm.
Answer: Dina of the segment DE is 5 cm.
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