In triangle CDE, angle C is 30 °, angle D is 45 °, СE = 5√2. Find DE.

univerkov | November 29, 2020 | education

1) Let’s draw the height of the CH.
2) Consider the SEN triangle, EH = 1/2 * 5 * √ (2) = 5 * √ (2) / 2
3) Consider a triangle ЕНD ED = [5 * √ (2) / 2] / [√ (2) / 2] = 5
Answer: 5

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