In triangle CDE, the sides CE and DE are equal, In triangle CDE, the sides CE and DE

In triangle CDE, the sides CE and DE are equal, In triangle CDE, the sides CE and DE are equal, the bisectors CM and DH meet at point A. Prove that triangle DAM = CAH

Since the sides DE and CE are equal, the angles CDE and DCE are also equal.

Let’s draw the bisectors. They will divide both left by equal angles, the total of which will be 4. That is, the MDH angle will be equal to the HCM angle, and DA = CA.

Proceeding from the fact that the sides DE and CE are equal, DМ = CH.

We have an equal angle and two sides, which means that DAM = CAH.

Answer: which is what was required to be proved.