In triangle DEF with right angle E, the height EH is drawn, equal to 2 cm.

In triangle DEF with right angle E, the height EH is drawn, equal to 2 cm. The length of the ED segment is 4cm. Find the sharp corners of the triangle DEF.

EH is the height of the triangle EFD, therefore, the segment EH is perpendicular to FD, then the triangle EHD is right-angled.
Then, in a right-angled triangle EHD, the length of the leg EH is equal to half the length of the hypotenuse ED, then the value of the opposite angle is 300.
SinEDH = EH / ED = 1/2.
The EDH is 30.
Then the angle EFD = 180 – 90 – 30 = 60.
Answer: The acute angles of the triangle are equal:
EFD = 60.
EDF = 30.