In triangle MKF, the side of KF is 2 times the median MD, so what is the angle M of triangle MKF?

Let the angle FKM = X0, then the angle KMD = X0, since the KDM triangle is isosceles.

KDM angle = (180 – 2 * X) 0.

The FDM angle is adjacent to the KDM angle, then the FDM angle = (180 – (180 – 2 * X) = 2 * X0.

The triangle FDM is isosceles, then the angle DFM = DMF = (180 – 2 * X) / 2 = (90 – X).

Angle KMF = KMD + DMF = X + 90 – X = 90.



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