In triangle MPK, angle P is 60% of angle K and angle M is 4 degrees greater than angle P. Find the value of angle P.

The sum of the angles of the triangle is 180º:

∠М + ∠Р + ∠К = 180º.

According to the condition of the problem, the angle P is 60% of the angle K, that is,

∠P = 0.6 * ∠K.

Angle M is 4º greater than angle P:

∠М = ∠Р + 4º = 0.6 * ∠К + 4º.

Consequently:

0.6 * ∠K + 4º + 0.6 * ∠K + ∠K = 180º;

2.2 * ∠К = 176º;

∠К = 80º.

We calculate ∠Р:

∠Р = 0.6 * 80º = 48º.

Answer: ∠Р = 48º.