In triangles ABC and ADC: BC = CD; angle BCA = angle DCA; Angle ADM = 80 degrees. Find ABC.

The ADM angle is adjacent to the ADC angle, the sum of which is 180, then the ADM angle = (180 – ADM) = (180 – 80) = 100.

In triangles ABC and ACD, side AC is common, side BC = CD, angle BCA = DCA, then triangles ABC and DCA are equal on two sides and the angle between them.

Then the angle ABC = ADC = 100 as similar angles of equal triangles.

Answer: Angle ABC is 100.



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