In triangles ABC, angle C is 90, AC = 27, sinA = 0.6 Find BC.

Determine the cosine of the angle BAC.

Cos2BAC = 1 – Sin2BAC = 1 – 0.36 = 0.64.

CosBAC = 0.8.

Then CosBAC = AC / AB.

AB = AC / CosBAC = 27 / 0.8 = 33.75 cm.

SinBAC = BC / AB.

BC = AB * SinBAC = 33.75 * 0.6 = 20.25 cm.

Answer: The length of the BC leg is 20.25 cm.



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