In triangles ABC, the angle C is 90 degrees. BC = √51, AB = 10. Find sinB.

By the Pythagorean theorem, we determine the length of the leg AC.

AC ^ 2 = AB ^ 2 – BC ^ 2 = 100 – 51 = 49.

AC = 7cm.

Then SinABC = AC / AB = 7/10.

Answer: The sine of the angle ABC is 7/10.



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