In voles, the gene for black color (A) dominates over the gene for red color, and the gene for short hair

In voles, the gene for black color (A) dominates over the gene for red color, and the gene for short hair (B) over the gene for long hair. Diheterozygous animals were crossed. In the male, gametes containing two dominant genes were found to be nonviable. We got 24 syavchik. How many animals will be: a) black and with short hair; b) black and with long hair; c) red in color and with short hair; d) red and with long hair? e) What kind of genotype splitting will be in the offspring?

According to the designations introduced in the condition of the problem, we will write down the diheterozygous sows – parents as AaBb.

A female hooded hoop will produce eggs ab, AB, aB and Ab.

Male sperm – spermatozoa ab, aB and Ab (AB – not viable according to the condition of the problem).

From crossing this pair of individuals, all probable offspring will look like this:

a) syavchiks with black short hair (3AaBb, 2AaBB, AABb) – 12 syavchiks = (24 * 6) / 12;

b) syavchiks with black long hair (Aabb, Aabbb) – 4 syavchik = (24 * 2) / 12;

c) syavchiks with red short hair (2aaBb, aaBB) – 6 syavchiks = (24 * 3) / 12;

d) syavchiks with red long hair (aabb) – 2 syavchik = (24 * 1) / 12.

Splitting by genotype in the offspring of these saplings is 6: 3: 2: 1.