In what case is a greater amount of heat required and by how much: for melting 1 kg

In what case is a greater amount of heat required and by how much: for melting 1 kg of copper or 1 g of silver, if both metals had a temperature of 20 degrees Celsius before heating?

Given:

m1 = 1 kilogram is the mass of copper;

m2 = 1 gram = 0.001 kilograms – the mass of silver;

T = 20 degrees Celsius – initial temperature of copper and aluminum;

q1 = 213 * 10 ^ 3 J / kg is the specific heat of copper;

T1 = 1085 degrees Celsius is the melting point of copper;

c1 = 381 J / (kg * C) – specific heat capacity of copper;

c2 = 235 J / (kg * C) – specific heat of silver;

q2 = 105 * 10 ^ 3 J / kg is the specific heat of silver;

T2 = 961 degrees Celsius is the melting point of silver.

It is required to determine the amount of heat for melting copper and silver.

In order to melt copper you need:

Q1 = c1 * m1 * (T1 – T) + q1 * m1 = 381 * 1 * (1085 – 20) + 213 * 10 ^ 3 * 1 = 405765 + 213000 = 618765 = 619 kJ.

In order to melt silver, you must:

Q2 = c2 * m2 * (T2 – T) + q2 * m2 = 235 * 0.001 * (961 – 20) + 105000 * 0.001 = 221 + 105 = 326 Joules.

Q1 – Q2 = 618765 – 326 = 618.4 kJ.

Answer: To melt copper requires 618.4 kJ more heat than silver.